((6x-3)/(5x^2))/((2x-1)/(10x))

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Solution for ((6x-3)/(5x^2))/((2x-1)/(10x)) equation: 


D( x )

10*x = 0

(2*x-1)/(10*x) = 0

5*x^2 = 0

10*x = 0

10*x = 0

10*x = 0 // : 10

x = 0

(2*x-1)/(10*x) = 0

(2*x-1)/(10*x) = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

5*x^2 = 0

5*x^2 = 0

5*x^2 = 0 // : 5

x^2 = 0

x = 0

x in (-oo:0) U (0:1/2) U (1/2:+oo)

((6*x-3)/(5*x^2))/((2*x-1)/(10*x)) = 0

(10*x*(6*x-3))/(5*x^2*(2*x-1)) = 0

( 10*x )

10*x = 0 // : 10

x = 0

( 6*x-3 )

6*x-3 = 0 // + 3

6*x = 3 // : 6

x = 3/6

x = 1/2

x in { 0} 

x in { 1/2} 

x belongs to the empty set

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